MATH SOLVE

4 months ago

Q:
# The length of rectangle is represented by x and the width by y. The square of the diagonal of the rectangle is equal to the sum of the squares of the length and the width. If the length is 25 meters and the diagonal is 45 meters, which quadratic equation could be used to determine the width of the rectangle?

Accepted Solution

A:

To solve this problem you must apply the proccedure shown below:

1- You have the following information given in the problem above:

- The square of the diagonal of the rectangle is equal to the sum of the squares of the length and the width.

- The length is 25 meters and the diagonal is 45 meters.

2- Therefore, you have:

x: diagonal of the rectangle.

x^2=l^2+w^2

3- You have:

w^2+l^2-x^2=0

w^2+(25)^2-(45)^2=0

w^2-1400=0

w=37.41

The answer is: w^2-1400=0

1- You have the following information given in the problem above:

- The square of the diagonal of the rectangle is equal to the sum of the squares of the length and the width.

- The length is 25 meters and the diagonal is 45 meters.

2- Therefore, you have:

x: diagonal of the rectangle.

x^2=l^2+w^2

3- You have:

w^2+l^2-x^2=0

w^2+(25)^2-(45)^2=0

w^2-1400=0

w=37.41

The answer is: w^2-1400=0