Q:

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 71°, a = 11 cm, c = 18 cm

Accepted Solution

A:
[tex]\boxed{\text{Area of the triangle:} \dfrac{a \times c \times sin(\measuredangle B)}{2}} \\ \\ A = \dfrac{a \times c \times sin(\measuredangle B)}{2} \\ \\ A= \dfrac{11 \times 18 \times sin71 ^o }{2} \\ \\ \\ Note : sin 71^o \approx 0,94 \\ \\ \\ A = \dfrac{198 \times 0,94}{2} \\ \\ A= \dfrac{186.12}{2} \\ \\ A=93.6 \ cm^2[/tex]